Mean Center and range around the Mean

804
4
Jump to solution
07-30-2017 12:48 AM
HushamMohamed
Occasional Contributor

I have an incident Point feature class.  I calculate the Mean Center.

Now I would like to  calculate:

25% of the incidents compared to the Mean Center  Then draw a circle to cover the 25%.

50% incidents compared to the Mean Center  Then draw a circle to cover the 50%

What percentage of the incidents  are closer to the xx office compared to yy office.

Any Idea or Model  or Python script.

Thanks

0 Kudos
1 Solution

Accepted Solutions
DanPatterson_Retired
MVP Emeritus
4 Replies
DanPatterson_Retired
MVP Emeritus

Standard Distance ... How it works... is what you want to use

HushamMohamed
Occasional Contributor

Thank you Dan,  Not exactly what I want, I am not Measuring the compactness of a distribution this way.  I am looking to draw some thing like buffers  according to the Percentage I mentioned from the mean Center- 

besides need to answer the question of : What percentage of the incidents  are closer to the xx office compared to yy office ( I have 2 offices, point feature.

Thanks

0 Kudos
DanPatterson_Retired
MVP Emeritus

Husham... that is what it will do... given points, the standard distance represents the distance (a circle radius) that encompasses a certain proportion of the distribution.  a 1 std deviation in both X and Y (check the formula for details) would suggest that 68% of the points would fall within that distance..  So for 50% you want about 0.6745 std distances.  The tool will actually create circles using defaults.  Otherwise you can use the radius to make your own buffers.

HushamMohamed
Occasional Contributor

Thanks

Will try that and get back to you.

0 Kudos