Proper case for names beginning with Mc, like McDavid

[Shauna-RaeBrown]

I have a featureclass of street names where all of the names are in uppercase.  I can set a label class using an expression STN begins with "MC%", but I want python to label the streets starting with MC to convert the label to proper case, for example, MCDAVID would be McDavid.  Does anyone have a suggestion for using python to do this?  I've already tried using [STN].title(), but that yields Mcdavid.  Thanks for the suggestions.

[AlfredBaldenweck]

You could always do a replace?

STN.replace("MC", "Mc")

[Shauna-RaeBrown]

That partially works.

STN.replace("MC", "Mc")

returns McDAVID.  What I want is McDavid.  Thanks for your help.  I'll keep trying. 

[AlfredBaldenweck]

Ohhh it's all in caps. Something like this should work?

I'm not putting in an if statement because you have it handled by the Label class query.

nam = STN.lower()
nam = nam.replace("mc", "Mc")
nam = nam[0:2] + nam[2].capitalize() + nam[3:]
return nam

Edited to change my slicing since I mixed it up a bit.

[Shauna-RaeBrown · Accepted solution]

Your little script is almost correct.  I had to change nam[0:1] to nam[0:2], because the "c" got skipped and yielded MDavid.  The following works, and yields McDavid.  Thanks so much!!!

def FindLabel ( [STN] ):
    nam = [STN].lower()
    nam = nam.replace("mc", "Mc")
    nam = nam[0:2] + nam[2].capitalize() + nam[3:]
    return nam

[AlfredBaldenweck]

That's what I get for posting without testing lol. Glad it works.

[RhettZufelt]

Probably a better way, but his is how I've handled that in the past.

I have a dictionary of the names that get whacked out when title casing and substitute the value when has a matching key.

subDict = { 
                "MCMURRAY ST": "McMurray St",
                "MCMURRAY AVE": "McMurray Ave",
                "MCINTOSH CT": "McIntosh Ct",
                "MCEWAN DR": "McEwan Dr",
                "MCPHERSON AVE": "McPherson Ave",
                "MCCLELLAN ST": "McClellen St",
                "BY-PASS": "Bypass Hwy         SR 240",
                "O'CONNOR ST":"O'Connor St",
                "MCMURRAY": "McMurray",
                "MCINTOSH": "McIntosh",
                "MCEWAN": "McEwan",
                "MCPHERSON": "McPherson",
                "MCCLELLAN": "McClellen",
                "O'CONNOR":"O'Connor"
                }
def FindLabel ( [Street] ):
      st = [Street]
      label = [Street].title()
      if st in subDict.keys():
             label = subDict[st]
      return label

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